Aptitude Percentage Question and answer

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6)One third of three fifth of two seventh of a number is 30. What will be 20% of that number

A) 140

B) 120

C) 180

D) 200

Answer:A) 120

Explanation:(1/3)*(3/5)*(2/7)*a=30
=>a=30/0.05=600
20% of 600 =120

7) What percent is 120 of 90? ?

A) 133 1/3%

B) 132 2/3%

C) 132 1/3%

D) None of these

Answer:A) 133 1/3%

Explanation: 120/90 = 4/3
4/3 × 100 = 400/3 = 133 1/3 %

8) Two students appeared at an examination. One of them secured 9 marks more than the other and his marks was 56% of the sum of their marks. What are the marks obtained by them ?

A) 43, 30

B) 42, 39

C) 42, 33

D) 44, 36

Answer:C) 42, 33

Explanation:Let the marks secured by the two students are x and (x + 9)
Then sum of their marks = x + (x + 9) = 2x + 9
Given that (x + 9) was 56% of the sum of their marks
=>(x+9) = 56/100(2x+9)
=>(x+9) = 14/25(2x+9)
=> 25x + 225 = 28x + 126
=> 3x = 99
=> x = 33
Then (x + 9) = 33 + 9 = 42
Hence their marks are 33 and 42

9) Three candidates contested an election and received 1136, 7636 and 11628 votes respectively. What percentage of the total votes did the winning candidate get ?

A) 51%

B) 57%

C) 69%

D) 84%

Answer:B) 57%

Explanation:Total number of votes polled = (1136 + 7636 + 11628) = 20400.
Percentage that winning candidate get from total number of votes = (11628 / 20400 x 100)% = 57%. .

10) The population of a town increased from 1,75,000 to 2,62,500 in a decade. The average percent increase of population per year is:

A) 10%

B) 3%

C) 21%

D) 5%

Answer:D) 5%

Explanation: Increase in 10 years = (262500 - 175000) = 87500
Increase percentage = (87500/175000 x 100) % = 50%
Hence, Required average = (50/10) % = 5%.

Exercise

Exercise 1

Exercise 2